A block of mass m is pressed against a vertic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For the block to be in equilibrium,the net vertical force must be zero.The forces acting on the block in the vertical direction are:$1$. Weight of

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(C) For the block to be in equilibrium,the net vertical force must be zero.The forces acting on the block in the vertical direction are:$1$. Weight of the block acting downwards: $mg$$2$. External upward force: $\frac{mg}{2}$$3$. Frictional force $f$ acting on the block.Since the block has a tendency to slide downwards (because $mg > \frac{mg}{2}$),the frictional force will act upwards.For equilibrium: $f + \frac{mg}{2} = mg$$f = mg - \frac{mg}{2} = \frac{mg}{2}$The normal force $N$ exerted by the wall on the block is equal to the horizontal pressing force: $N = mg$.The maximum possible static friction is $f_{\max} = \mu N = \mu mg$.For equilibrium,the required friction must be less than or equal to the maximum static friction:$f \leq f_{\max}$$\frac{mg}{2} \leq \mu mg$$\mu \geq \frac{1}{2} = 0.5$Therefore,the minimum coefficient of friction is $0.5$.

$A$ block of mass $m$ is pressed against a vertical wall and is in equilibrium. An external upward force of $\frac{mg}{2}$ is applied to the block. The minimum coefficient of friction $\mu$ required is:

Similar Questions

$A$ block of mass $1 \, kg$ is projected from the lowest point up along an inclined plane with an angle of inclination $45^{\circ}$ and coefficient of friction $\mu = 0.5$. If $g = 10 \, ms^{-2}$,the retardation experienced by the block is ............. $ms^{-2}$.

$A$ weight $W$ can be just supported on a rough inclined plane by a force $F$ either acting along the plane or horizontally. If $\theta$ is the angle of friction,then $F / W$ is

Two blocks $A$ and $B$ are released from the top of a rough inclined plane so that $A$ slides along the plane and $B$ falls down freely. Which will have higher velocity on reaching the ground?

$A$ block is projected up an inclined plane of angle $\theta = 30^o$ with an initial velocity of $5 \, m/s$. It comes to rest in $0.5 \, s$. What is the coefficient of friction?

$A$ block is stationary on a rough inclined plane. How many forces are acting on the block?

Vedclass Test Series

Exam Paper Generator

Online Exam Module